Q1. Find whether the number 3948 is divisible by 6 or not. Solution A number is divisible by 6 only if it is divisible by 2 and 3. Consider the number 3948. Since its units place digit is 8, which is even. So the number 3948 is divisible by 2. Again, sum of digits = 3 + 9 + 4 + 8 = 24. Since, 24 is divisible is 3. So the number 3948 is divisible by 3. Thus, the number is divisible by both 2 and 3. Hence, 3948 is divisible by 6. Q2. In the following addition, find A. Solution Consider: At one's place, A + 3 = _1 So think of a number which when added to 3 gives one's place as 1. Such a number is 8 as 8 + 3 = 11 Taking, A = 8, we obtain the addition as below: Q3. Using the digits 4, 0 and 5, form all possible 3 digit numbers without repeating the digits. Also, classify them in a multiple of 2 and 3. Solution Digits are: 4, 0, 5 3 digit numbers are: 405...