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Q1. A linear graph is given by the relation y = 3x + 6. Find the value of y if the value of x is 5. 
  • 1) 15
  • 2) 21
  • 3) 3
  • 4) 18

Solution

Put x = 5 in y = 3x + 6We get y = 21. 
Q2. A bank gives 10% simple interest on the deposits. Draw a graph to show the relation between the sum deposited and the simple interest earned.

Solution

To draw the graph we assume the deposit sum to be Rs 1000, Rs 2000, Rs 3000 and Rs 4000. Now we calculate the SI for 1 year for the sum deposit. Sum deposit SI Rs 1000 Rs 2000 Rs 3000 Rs 4000 Plotting the points (1000, 100), (2000, 200), (3000, 300) and (4000, 400), we get the graph as below:
Q3. Observe the graph:   What is the difference between the lowest marks of Rishit and Samyak? 
  • 1) 15
  • 2) 10
  • 3) 20
  • 4) 5

Solution

Lowest marks of Rishit is 30.Lowest marks of Samyak is 45.Hence, difference between them is 45 - 30 = 15. 
Q4. Following table shows the relation between number of books sold and the profit earned on it. Number of books sold 3 6 15 Profit earned (in Rs) 15 30 75 Draw the graph for above data and find the profit earned if 12 books are sold.

Solution

Plotting the points (3, 15), (6, 30) and (15, 75), we get the graph as below: From the graph, we find that the profit earned on sale of 12 books is Rs 60.
Q5. Draw the triangle XYZ where X(4, 5), Y(-4, 2) and Z (-3, -4).

Solution

Plotting the points and joining them, we get the following triangle XYZ.
Q6. The following graph shows the amount of potatoes consumed in kg. Read the graph and answer the following questions. (a) On which day did maximum amount of potatoes consumed?(b) On which day the consumption of potatoes went down?(c) What is the combine consumption of potatoes on Monday, Tuesday and Wednesday?

Solution

(a) Maximum consumption of potatoes was on Sunday.(b) On Thursday, the consumption of potatoes went down.(c) The combined consumption of potatoes on Monday, Tuesday and Wednesday = 15 + 20 + 30 = 65 kg
Q7. The following graph shows the sale of a particular toy. Study the graph and answer the following questions: (a) The difference of sale in the month of February and March. (b) Total sale in four months.

Solution

(a) Sale in February = 125 And, sale in March = 115 So, the difference of sale = 125 - 115 = 10 (b) Total sale = 105 + 125 + 115 + 155 = 500


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